## Euclid's Elements of Geometry: From the Latin Translation of Commandine. To which is Added, a Treatise of the Nature and Arithmetic of Logarithms ; Likewise Another of the Elements of Plain and Spherical Trigonometry : with a Preface ... |

### Inni boken

Side 24

1 THEO R E M. if two Triangles

1 THEO R E M. if two Triangles

**have two Angles of the one equal to two Angles of the other**, each to each , and one Side of the one equal to one side of the other , either the Side lying between the equal Angles , or which subtends one ... Side 66

But the Right An05.1 . gle AFE is equal to the Right Angle BFE ; therefore the two Triangles E AF , EBF ,

But the Right An05.1 . gle AFE is equal to the Right Angle BFE ; therefore the two Triangles E AF , EBF ,

**have two Angles of the one equal to two Angles of the other**, and the Side EF is common to both . Wherefore the other Sides * 26. Side 113

Then fince the Angle HC is equal to the Angle KCF ; and the Right Angle FHC equal to the Right Angle FKC ; the two Triangles FHC , PK Cîhall

Then fince the Angle HC is equal to the Angle KCF ; and the Right Angle FHC equal to the Right Angle FKC ; the two Triangles FHC , PK Cîhall

**have two Angles of the one equal to two Angles of the other**, and one side of the one equal to ... Side 230

Therefore the two Triangles MDF , HAC ,

Therefore the two Triangles MDF , HAC ,

**have two Angles of the one equal to two Angles of the other**, each to each , and one Side of the one equal to oné Side of the other , viz . that which is subtended by one of the equal Angles ...### Hva folk mener - Skriv en omtale

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### Vanlige uttrykk og setninger

added alſo Altitude Angle ABC Angle BAC Baſe becauſe Center Circle Circle ABCD Circumference common Cone conſequently contained Cylinder demonſtrated deſcribed Diameter Difference Diſtance divided double draw drawn EFGH equal equal Angles equiangular Equimultiples exceeds fall fame firſt fore four fourth given greater half join leſs likewiſe Logarithm Magnitudes Manner Multiple Number oppoſite parallel Parallelogram perpendicular Place Plane Point Polygon Priſm produce Prop Proportion PROPOSITION proved Pyramid Ratio Rectangle remaining Right Angles Right Line ſaid ſame ſame Reaſon ſay ſecond Segment ſhall ſhall be equal Sides ſimilar ſince Sine Solid Sphere Square ſtand taken Term THEORE thereof theſe third thoſe thro touch Triangle Triangle ABC Unity Vertex Wherefore whole whoſe Baſe

### Populære avsnitt

Side 188 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.

Side 156 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.

Side 61 - DBA ; and because AE, a side of the triangle DAE, is produced to B, the angle DEB is greater (16.

Side 148 - ... therefore the angle DFG is equal to the angle DFE, and the angle at G to the angle at E : but the angle DFG is equal to the angle ACB...

Side 96 - About a given circle to describe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle; it is required to describe a triangle about the circle ABC equiangular to the triangle DEF.

Side 17 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...

Side 206 - CD; therefore AC is a parallelogram. In like manner, it may be proved that each of the figures CE, FG, GB, BF, AE, is a parallelogram...

Side 227 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.

Side 160 - ABG ; (vi. 1.) therefore the triangle ABC has to the triangle ABG the duplicate ratio of that which BC has to EF: but the triangle ABG is equal to the triangle DEF; therefore also the triangle ABC has to the triangle DEF the duplicate ratio of that which BC has to EF. Therefore similar triangles, &c.

Side 89 - If from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.